in fig, l parallel m, angle ABC=35 degree and angle APQ=40degree .find x
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Step-by-step explanation:
∠ACB = 40° ---( l II m and PC is transversal, ∴ alternate interior angle)
in triangle ABC, ∠CAB + ∠ABC + ∠ACB = 180° ----- (Angle Sum Property)
∠CAB + 35° + 40° = 180°
∠CAB + 75° = 180°
∠CAB = 180°-75°
∠CAB = 105°
∠CAB + ∠QAC = 180° --- (linear pair)
105° + ∠QAC = 180°
∠QAC = 180° - 105°
∠QAC = 75°
∴ ∠x = 75°
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answer is in attached pic
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