Question

In fig; line AB and CD intersects at O. if <AOC+<BOE=70° and <BOD=40°; find <BOE and refex <COE.
please help me please

Answer 1

Answer:

Step-by-step explanation:

<AOC+<BOE+<COE=180[angle

sum property]

70+<COE=180

<COE=110

CD is a straight line

<COE+<BOD+<BOE=180

[Linear pair]

110+40+<BOE=180

<BOE =30

Reflex<COE = 360-<COE

360-110=250

Answer 2

Question :-

In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

Answer :-

Since AB is a straight line,

∴ ∠AOC + ∠COE + ∠EOB = 180°

or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]

or ∠COE = 180° – 70° = 110°

∴ Reflex ∠COE = 360° – 110° = 250°

Also, AB and CD intersect at O.

∴∠COA = ∠BOD [Vertically opposite angles]

But ∠BOD = 40° [Given]

∴ ∠COA = 40°

Also, ∠AOC + ∠BOE = 70°

∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°

Thus, ∠BOE = 30° and reflex ∠COE = 250°.

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