Question

In Fig ∆ MNO is a right-angled triangle. Its legs are 6 cm and 8 cm long. Length of perpendicular NP on the side MO is

Answer 1

Answer:

Hii

Step-by-step explanation:

by pythagoras theorem

length of side MO

MO²= MN²+ NO²

MO²= 8²+6²

MO²= 64+36

MO²=100

MO= 10 cm

area of the triangle MNO

(MN×NO)/2

(8×6)/2 =48/2 =24cm²

area of the triangle MNO

(NP×MO)/2

24cm² = (NP×10)/2

48 = (NP×10)

48/10 = NP

= 4.8cm

I hope it helps you..

Answer 2

Answer:

Step-by-step explanation:

8²-6²= length of perpendicular ²

64-36= length of perpendicular ²

28 = length of perpendicular ²

√28 = length of perpendicular

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