Question

in fig o is center of a circle angle aob = 50° and angle acd = 20° find angle boc?

Answer 1

As OB=OA BOTH RADIUS
OBA=OAB
OAB=50

AS OC=OA both RADIUS
OCA=OAC
OAC=20

BAC=70

ANGLE O =2(BAC).......CENTRAL ANGLE PROPERTY
ANGLE O=140

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