Question

In fig.,O is the centre of a circle.The area of sector OAPB is 5/18 of the area of the circle. Find x.

Answer 1

GIVEN:
Area of sector OAPB = 5/18 × Area of Circle
Let the central angle (θ) = x

Area of sector = (θ /360) ×πr²
Area of circle = πr²

Area of sector OAPB = 5/18 × Area of Circle
(x /360) ×πr² = 5/18 × πr²
(x /360) = 5/18  [ by cross multiplying]
18x = 5 × 360
x = (360 × 5)/18 = 20 × 5 = 100

Hence , the value of x is 100°

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Answer 2

here is your answer....