In Fig O is the centre of the circle and A B C are three points on circle Find AngleAOC
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Answer:
Angle AOC = 116°.
Step-by-step explanation:
Join AO.
Now, in ∆ AOC, AO = CO ...(radii of the circle)
Therefore, ∆ AOC is an isosceles ∆
< OAC = < OCA = 32°.
{ Angles opposite to equal sides are equal.}
< AOC = 180 - (32 + 32)
< AOC = 180 - 64 = 116°
Hence, Angle AOC = 116°
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