Question

In fig O is the centre of the circle AT and BT are the tangents drawn from an external point T,if angle OAB=30degree ,then the measure of angle ATB. Is​

Answer 1

Angle TAO=90 and Angle TBO=90

And ATBO is a quadrilateral

So,angle AOB=30 then 180-30=150

AngleATB=150

Because we know that tangents make 90 degree at centre.

And, Interior sum of quadrilateral is 360.

So,90+90+30+angleATB=360

So,angle ATB=360-210=150

Answer 2

Answer:

Given : OAB = 30 degree

AT and BT are the two tangents

w.k.t , radius is perpendicular to the tangent .

OA is perpendicular to AT

OB is perpendicular to BT

now , sum of all the interior angle = 360 degree .

OAT+OBT+ATB+OAB = 360

90+90+30+ATB = 360

210+ATB = 360

ATB = 360 ‐ 210

ATB = 150