Question

In fig. O is the centre of the circle PQ is a chord and PT is tangeny to the circle at P.If
Answer please....

Answer 1

 ∠OPQ = (180 - 70)/2 = 55°
 ∠OQP = 55°                       ( ∵ OQP IS AN ISOSCELES TRIANGLE)
∠TPQ  =  90° - 55° = 35°   (∵ RADIUS TO TANGENT IS PERPENDICULAR)