Question

In fig. OAB is a sector of a circle of radius 10.5 cm. Find the perimeter of the sector.

Answer 1

PERIMETER : The length of the boundary of the figure.

GIVEN:
Radius of  a Sector of a circle= OA = OB= 10.5 cm
Central angle (θ) = 60°

If the radius of a circle is r and length of the arc is l, then
Length of the arc(AB), (l) = (θ /180) × πr

l = (60/180) × (22/7) × 10.5
l =( ⅓) × 22 × 1.5
l = 22 × .5 = 11 cm

PERIMETER OF THE SECTOR = length of the Arc(AB)  + OA +OB

Perimeter of the Sector = 11 +10.5 + 10.5
= 11 + 21
= 32 cm.

Hence, the Perimeter of the Sector is 32 cm.

HOPE THIS WILL HELP YOU...

Answer 2

Answer:PERIMETER : The length of the boundary of the figure.

GIVEN:

Radius of  a Sector of a circle= OA = OB= 10.5 cm

Central angle (θ) = 60°

If the radius of a circle is r and length of the arc is l, then

Length of the arc(AB), (l) = (θ /180) × πr

l = (60/180) × (22/7) × 10.5

l =( ⅓) × 22 × 1.5

l = 22 × .5 = 11 cm

PERIMETER OF THE SECTOR = length of the Arc(AB)  + OA +OB

Perimeter of the Sector = 11 +10.5 + 10.5

= 11 + 21

= 32 cm.

Hence, the Perimeter of the Sector is 32 cm.

HOPE THIS WILL HELP YOU...