in fig PA and PB are two tangents to circle and /_ASB=60° then find the measure of /_ APB
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ariyanmishra1996:
i can't understand
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Answered by
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Given <ASB = 60°
Join OA, OB radii.
We know that ,
<AOB = 2<ASB
= 2×60°
= 120°
Now ,
In AOBP Quadrilateral ,
<OAP+<AOB+<OBP+<APB=360°
=> 90°+120°+90°+<APB=360°
=> 300° + <APB = 360°
=> <APB = 360° - 300°
=> <APB = 60°
••••
Join OA, OB radii.
We know that ,
<AOB = 2<ASB
= 2×60°
= 120°
Now ,
In AOBP Quadrilateral ,
<OAP+<AOB+<OBP+<APB=360°
=> 90°+120°+90°+<APB=360°
=> 300° + <APB = 360°
=> <APB = 360° - 300°
=> <APB = 60°
••••
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i want to know how ASB and APB equals to 180° explain plss
please explain
is it clear now .
thank you so much
i have marked your answer as brilliant
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Answered by
1
ANGLE ASB + ANGLE SBP + ANGLE BPA + ANGLE PAS = 360* [ ANGLE SUM PROPERTY OF QUADRILATERALS]
ANGLE PAS = 90* [ RADIUS PERPENDICULAR TO TANGENT]
ANGLE SBP = 90* [ RADIUS PERPENDICULAR TO TANGENT]
ANGLE ASB = 60* [GIVEN]
THEREFORE, 60*+90*+90*+ANGLE APB = 360*
ANGLE APB = 360-240
= 120*
pas is not radius??
means AS and SB are not radii...
how can you say that angle PAS and angle SBP is 90°
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