Question

In fig,PAQ is a tangent to a circle with centre O at a point A on centre as shown in centre. If angle OBA=35 find the value of BAQ and ACB



PLZZZZ HELP ME IN THIS QUESTION

Answer 1

Answer:

Step-by-step explanation:

Proof :

OA=OB (radii of same circle)

Angle OAB=35 (angle opposite to

                          equal sides of a

                          triangle are equal)

But,

OBA+AOB+OAB=180

35+AOB+35=180

AOB=180-70

AOB=110

ACB=1/2AOB (Degree measure

                       theorem)

ACB=1/2 * 110

ACB=55

=> ACB=55

BAQ=ACB=55 (Angles in the same

                         segment)

Answer 2

Answer:

Step-by-step explanation:

Saumil123Ambitious

Know the answer? Add it here!

Sohankendre6030Helping Hand

Answer:

Step-by-step explanation:

Proof :

OA=OB (radii of same circle)

Angle OAB=35 (angle opposite to

equal sides of a

triangle are equal)

But,

OBA+AOB+OAB=180

35+AOB+35=180

AOB=180-70

AOB=110

ACB=1/2AOB (Degree measure

theorem)

ACB=1/2 * 110

ACB=55

=> ACB=55

BAQ=ACB=55 (Angles in the same

segment)