Question

. In fig. POQ in a line, ray OR perpendicular to line PQ, OS is another ray lying between rays OP and OR PT ROS = ( ∟QOS - ∟POS )

Leaving brainly....​

Answer 1

Answer:

∠ROS=90  

∘

−∠POS−(i)

∠QOS=∠QOR+∠ROS=90  

∘

+∠ROS

⇒90  

∘

=∠QOS−∠ROS−(ii)

Substituting (ii) in (i) we get

∠ROS=∠QOS−∠ROS−∠POS

⇒2∠ROS=∠QOS−∠POS

⇒∠ROS=  

2

1

​  

(∠QOS−∠POS)

Explanation:

Answer 2

Answer:

It is the correct answer.

Explanation:

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