Question

In fig, PQ and PR are tangents to the circle with centre O at the points Q and R respectively

and S is a point on the circle such that

<SQL = 50°
and <SRM =60°,then what is the measure of <QSR ?​

Answer 1

Answer:

Here ∠OSQ = ∠OQS = 90°–50° = 40° and ∠RSO = ∠SRO = 90° – 60° = 30°.  Therefore, ∠QSR = 40° + 30° = 70°.

Answer 2

Answer:

QSR=70°

Step-by-step explanation:

HERE

SO,

WE TAKE

(angle)OSR=OQS=90°-50°=40°

And

(angle)RSQ=SRO=90°-60°=30

And

(Angle)QSR=40°+ 30°= 70

Thank you