in fig PQ= PR and angle q= angle R prove that triangle pqs = triangle prt, qs=rt
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Here is your answer In ∆PQS and ∆PRT, <P = <P (Common) PQ = PR (Given) <Q = <R (Given) Therefore, ∆PQS Congruent ∆PRT (A.S.A rule) Hence, => QS= RT (C.P.C.T) Proved. Be Brainly
genius6130:
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Answer:
ΔPQS≅ΔPRT ; QS = RT
Step-by-step explanation:
Given that PQ=PR and ∠Q = ∠R.
We have to solve this by using congruency theorem.
- congruence of triangles: When two triangles are similar to each other in shape and size, they are said to be congruent if all three corresponding sides are equal and all three corresponding angles are equal.
- Types of congruence rules:
- SSS (side-side-side)
- SAS(sides-angle-side)
- ASA(angle-side-angle)
- AAS(angle-angle-side)
- RHS(right angle-hypotenuse-side)
Consider ΔPQS and ΔPRT
∠P is common in both the triangles.
Given that PQ = PR and also ∠Q = R
∠P = ∠P ( Angle )
PQ = PR (Side)
∠Q = ∠R (Angle)
so, ΔPQS≅ΔPRT.
ΔPQS≅ΔPRT means that,
PQ = PR
QS = RT
PS = PT
Hence proved that QS = RT.
for more examples about congruency of triangles visit the link below :
https://brainly.in/question/4777330
statement that describe the congruent triangles :
https://brainly.in/question/26826873
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