Math, asked by raj644478, 1 year ago

In fig.PQ,RS and UT are parallel lines. i) if c=57 and a=c/3,find the value of d. ii)if c=75 and a=2c/5,find b.​

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Answered by bhagyashreechowdhury
38

Given:

PQ, RS and UT are parallel lines

To find:

i) if c=57 and a=c/3,find the value of d.

ii)if c=75 and a=2c/5,find b.​

Solution:

(i) Finding the value of d:

Here → c = 57° and a = \frac{c}{3}

∴ a = \frac{c}{3} = \frac{57}{3} = 19°

We have PQ // UT

∠c = ∠QPT ...... [alternate angles]

Also, ∠QPT = a + b

c = a + b

⇒ 57° = 19° + b

b = 38°

Now, we have PQ // RS

∠b + ∠d = 180° ..... [∵ when the line are parallel, then the sum of co-interior angles is equal to 180°]

 

Substituting b = 38°, we get

38° + ∠d = 180°

⇒ ∠d = 180° - 38°

∠d = 142°

Thus, the value of d = 142°.

(ii) Finding the value of b:

Here → c = 75° and a = \frac{2c}{5}

∴ a = \frac{2c}{5} = \frac{2\:\times\:75}{5} = 30°

We have PQ // UT

∠c = ∠QPT ...... [alternate angles]

Also, ∠QPT = a + b

c = a + b

⇒ 75° = 30° + b

b = 45°

Thus, the value of b = 135°.

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Answered by Anonymous
4

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