Question

in fig. PQ//SR,PQ is perpendicular to PS. angle QRT= 65 & angle SQR=28 then find the values of x & y

Answer 1

Here answer

Here measure angle y = 28 bec it is form by alternative angle ( form Z )

And in triangle PSQ,
m< P + m< S + m< Q = 180
90 + 28 + m< Q = 180
118 + m< Q = 180
m< Q = 62

Hence m m

Ok if it's help then mark me as brainiest and thanks

Answer 2

GIVEN:-

$\large\sf{PQ||SR}$

$\large\sf{\angle{SQR}=28°}$

$\large\sf{\angle{QRT}=65°}$

━━━━━━━━━━━━━━━

➡$\large\sf{\angle{PQR}=\angle{QRT}(A.I.A)}$

➡$\large\sf{x+28°=65°}$

➡$\large\sf{x=65°-28°}$

➡$\large\sf{x=37°}$

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➡$\huge\sf\green{In\:∆PQS}$

➡$\large\sf{\angle{PQS}+\angle{PSQ}+\angle{SPQ}=180°}$

➡$\large\sf{37°+\angle{PSQ}+90°=180°}$

➡$\large\sf{\angle{PSQ}+127°=180°}$

➡$\large\sf{\angle{PSQ}=53°}$