in fig., PQ ║ XY. If XZ is 8 cm, ZP is 2 cm, YZ is 16 cm, find ZQ
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bro where is the figure???
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Given : PQ || XY
XZ is 8 cm, ZP is 2 cm, YZ is 16 cm,
To Find : ZQ
Solution:
PQ || XY
=> ∠X = ∠P & ∠Y = ∠Q ( corresponding angles)
∠Z = ∠Z is common
Hence Δ PQZ ≈ Δ XYZ (AAA)
Similar Triangles: corresponding angles are congruent and the corresponding sides are proportional
=> ZP/XZ = ZQ/YZ
=> 2 / 8 = ZQ / 16
=> 1/ 4 = ZQ / 16
=> 4 = ZQ
ZQ = 4cm
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