Question

In fig. /_PQR=90° seg PS perpendicular to seg PR then find x, y, z.​

Answer 1

Step-by-step explanation:

In ΔPQR,

${18}^{2} = {z}^{2} + {y}^{2}$

$324 = {z}^{2} + {y}^{2}$

In ΔQSR,

${y}^{2} = {8}^{2} + {x}^{2} \\ {y}^{2} = 64 + {x}^{2}$

In ΔPQS,

${z}^{2} = {x}^{2} + {10}^{2} \\ {z}^{2} = {x}^{2} + 100$

On solving these three equation you will get the values of x y and z

Answer 2

Step-by-step explanation:

Hope the answer is correct . Let me know if there is any error. Thanks.