In fig., q || r and p is transversal. If <1 and <2, 3 : 2 then the values of <3 and <4 are:
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∠3 = 108°
∠4 = 72°
Given:
q || r and p is transversal
∠1 and∠2 is in ratio 3 : 2
To find:
Find the values of ∠3 and ∠4
Let the ratio be x,
∠1 = 3x
∠ 2 = 2x
Sum of all the angles on the same side of a straight line is equal to 180°
∠1 and ∠2 are the only angles on the same side of line q,
So, ∠1 + ∠2 = 180°
3x + 2x = 180
5x = 180
x = 180/5
x = 36
∠1 = 3x = 3*36 = 108°
∠2 = 2x = 2*36 = 72°
Now, q || r and p is transversal.
Vertically opposite angles are equal so,
∠1 = ∠3
∠2 = ∠4
so, ∠3 = ∠1 = 108°
∠4 = ∠2 = 72°
∠3 = 108°
∠4 = 72°
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