in Fig. QR and RS are equal chords of a circle with centre 'O' if angle
ROS = 40, then find angle QRP.
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Answer: ∠PQR = 80°
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step-by-step explanation:
We know, the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle.
Hence,In given circle,
∠POR=2∠PQR
Therefore ∠POR=2×40°=80°
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