In fig. QR is a common tangent to the given circles, touching externally at the point T. The tangent at T meets QR at P. if PT = 3.8 cm, then the length of QR (in cm) is
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hey mate here is your solution
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we know that PT is 3.8cm long and we akso know that PT=PR=PQ because P is the common point from where tangents are drawn to the circles and tangents drawn from a point are always equal. So now PQ and PR both are equal to 3.8cm and since QR=QP+PR
QR=3.8+3.8
=7.6cm
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