Question

In fig., ray OE bisects/_AOB and OF is a ray opposite to OE.Show that /_FOB =/_FOA.​

Answer 1

• Here ,EF is a straight line
• moreover, OE bisects Angle AOB
• Therefore, Angle AOE = Angle BOE
• let this be" x "
• now, Angle AOF = 180°- Angle x (LINEAR PAIR)
• SIMILIARLY, ANGLE BOF = 180°- x , as FE is a straight line, by linear pair
• therefore Angle AOF = Angle BOF =180°-x