Question

In fig. RS is diameter of the circle ,PM is parallel to RS and ∠ = 30°,find ∠


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Answer 1

Answer:

Join RN and MS

∠RMS=90

∘

[Angle in a semi-circle is a right angle]

So, by angle sum property of ∆RMS

∠RMS=90

∘

–29

∘

=61

∘

And,

∠RNM=180

∘

–∠RSM=180

∘

–61

∘

=119

∘

[Pair of opposite angles in a cyclic quadrilateral are supplementary]