Physics, asked by rajarshipatra7825, 1 year ago

In fig shown the potential drop across 3 microfarad capacitor is?

Answers

Answered by Anonymous
0

Charging path of capcitors is shown in fig.(a). It can be seen that only C3 and C7 are getting charged.

All other capacitors are getting shorted.

Hence as shown in fig.(b),  we have two capacitors in series combination which is connectred across 40V potential difference.

 

Equivalent capacitance Ceq of this series combination is given by:-  Ceq = (36×8)/(36+8) = 6.55μF

 

Charge across each capacitors = 6.55×40 = 262 μC;

 

Potential across 8μF capacitor = 262/8 = 32.75 V

Answered by Shhii
0
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