Math, asked by Shumaila98, 7 months ago

In fig. the side AB of parallelogram ABCD is produced to a point X such that BX=AB. Prove that DX bisects BC

Answers

Answered by rashi1933

3

Step-by-step explanation:

( In proof

3rd line - angle DCE = angle XBE ( DC // BX internal alternate angles)

hope this helps

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