Math, asked by rupaligodase79, 5 hours ago

In Fig, the sides AB and AC of ∆ABC are produced to points E and D respectively. If bisectors BO and CO of ∠ CBE and ∠ BCD respectively meet at point O, then prove that ∠ BOC = 90° – (1 /2)∠BAC​

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Answered by Irobuster143
3

hope it helps plz mark me brainliest

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