Question

in fig. this is the mid point of line segment ABCD prove that AC=BD and ACIIBD

Answer 1

In triangle ACO & triangle BDO

AO=BO (o is midpoint of AB)

/_AOC=/_BOD(VOA)

CO=DO(o is mid point of DC)

so, triangle AOCis congruent to triangle BOD.

AC=BD(CPCT)

/_ACO=/_BDO(CPCT)

therefore AC ll BD(If alternate angles are equal then the lines are parallel)


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