Question

In fig triangle abc congruent to triangle def area of triangle abc =121 cm and area of triangle def =64cm if median of triangle abc is 12.1cm

Answer 1

Answer:

Step-by-step explanation:

∆ABC~∆DEF...,..........given

Now,

By similar triangle theorem we get,

∆ABC2 /∆ DEF2 = BC2 / EF2

64/121 = BC2/(15.4)2

By taking square roots of both sides,

8/11= BC/15.4

By cross multiplication,

(15.4×8)/11 = BC

BC=11.2

therefore value of BC is 11.2