Question

In fig. triangle ABC is right angled at B and AB=50cm, BC=50 root 3cm, find the value of x. ​

Answer 1

Answer:

Step-by-step explanation:

hi

you know  trigonometry then you can solve

tan(x)=opposite side/adjacent side

Tan(x)=AB/BC

tan(x)=50/50$\sqrt{3}$

Tan(x)=1/$\sqrt{3}$

x=30degrees

Answer 2

Answer:

The value of x is 30°.

Step-by-step explanation:

Trigonometric ratios are

sin(x) = opposite side/hypotenuse

cos(x) = adjacent side/hypotenuse

tan(x) = opposite side/adjacent side

Given that the triangle ABC is right angle at B

that is angle B is 90°.

and AB =  50cm

BC = 50$\sqrt{3}$ cm

We have to find the value of x in the given figure.

In ΔABC,

tan(x) =opposite side/adjacent side =  $\frac{AB}{BC}$

tan(x) = $\frac{50}{50\sqrt{3} }$

$tan(x) =\frac{1}{\sqrt{3} } \\x = tan^{-1} (\frac{1}{\sqrt{3} } )$

x = 30°

Hence, the value of x is 30°.