In fig , ∠X =62° , ∠XYZ = 54° . If YO and ZO are bisectors of ∠XYZ and ∠XZY respectively of XYZ,find ∠OZY and ∠YOZ *
30° ,140°
32° , 120°
32°, 121°
none
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So ,
Step-by-step explanation:
As we know
Sum of ∆ = 180°
X+ Y + Z = 180°
angle Z = 180-(62+54)
angle Z = 180° - 116°
angle Z = 64°
Therefore, angle OZY= 64°/2
= 32°
as OZ is bisector of angle XZY
AND
as YO is bisector of angle XYZ
Therefore, angle XYZ= 54°/2
54°/2 = 27°
Now ,angle YOZ =
Angle O + 32 + 27 = 180°
Angle O = 180-(32+27)
Angle O = 180-59
angle O = 121°
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