in fig12.39 ABCD is a rhombus in which diagonal AC and BD intersect at O if OD=6cm AD=10 cm and BD=AC find
(AC+BD)
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Answer:
According to quesion,
AB=10, BD=16
From figure,
AO+OC=AC
& AO=OC
=> 2AO=AC
In △AOB, from pythagorous
AB2=AO2+BO2
=> 100=64+AO2
=> AO=6
Since, AC=2OA,
Hence, AC=12cm
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Ac =12 cm
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