In fig6.18, if LM || CB and LN||CD,prove that AM/AB=AN/AB
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Consider ∆ABC,
Angle ALM = Angle ACB
Angle A = Angle A ( Common)
Angle AML = Angle ABC
So The sides opposite to equal angles will be similar
AM/AB
Consider ∆ABC and ∆ADC,
AM=AN(angles are equal)
So AB=AD
Like in ∆ABC,
Consider ∆ADC,
We Get
AN/AD
Since ∆ABC = ∆ADC
AM/AB=AN/AD
AM/AB=AN/AB(AD=AB)
Proved....
ayshadiya:
Ok
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