Question

In figure 1.13 BC perpendicular to AB, AD perpendicular to AB, BC=4,AD=8,then find A(triangle ABC) \A(triangle ADB)​

Answer 1

Answer:

from the figure

BC perpendicular to AB

AD perpendicular to AB

BC = 4

AD = 8

\frac{A(∆ABC)}{A(∆ADB)} = \frac{BC }{AD}

\frac{A(∆ABC)

}{A(∆ADB) } = \frac{4}{8}

\frac{A(∆ABC)}{A(∆ADB)} = \frac{1}{2}