Question

in Figure 1.
2. When a dice is thrown, list the probability of an event of
getting the following outcomes.
i. A number greater than 4
ii. A composite number
iii. A number not less than 3​

Answer 1

$\large\bigstar\boxed{\bf{\green{☣\:GIVEN\:☣}}}$

$\star\bold\pink{ A\:dice\:is\:thrown}$

$\large\bigstar\boxed{\bf{\green{⏮\:To\:Find\:⏭}}}$

i. A number greater than 4

ii. A composite number

iii. A number not less than 3

$\large\bigstar\boxed{\bf{\green{⏮\:SOLUTION\:⏭}}}$

WE KNOW THAT THE FORMULA OF PROBABILITY IS P(E) :-

$\huge\frac{no \:of\: favourable\: outcomes}{total\: no\: of \:possible\: outcomes}$

So the possible outcomes are 1,2,3,4,5,6

Total no of possible outcomes = 6

$\huge\bold\red{\underline{\underline{ATQ,}}}$

i)) A number greater than 4

Among 1,2,3,4,5,6 we can see that 5,6 are greater than four.

So the favourable outcomes are 2.

So by putting the formula,

$\large{P(E) =}$$\huge\frac{2}{6}$

$\Longrightarrow\large{P(E) =}$$\huge\frac{1}{3}$

ii)) A composite number

Among 1,2,3,4,5,6 we can see that 4,6 are composite number.

So the favourable outcomes are 2.

So by putting the formula,

$\large{P(E) =}$$\huge\frac{2}{6}$

$\Longrightarrow\large{P(E) =}$$\huge\frac{1}{3}$

iii)) A number not less than 3

Among 1,2,3,4,5,6 we can see that 4,5,6 are not less than 3.

So the favourable outcomes are 3.

So by putting the formula,

$\large{P(E)= }$$\huge\frac{3}{6}$

$\Longrightarrow\large{P(E)= }$$\huge\frac{1}{2}$

$\large\bigstar{\sf{\green{\underline{\underline{⏮\:The\:Answers\:Are\:⏭}}}}}$

i)) $\</strong><strong>h</strong><strong>u</strong><strong>g</strong><strong>e</strong><strong>\frac{1}{</strong><strong>3</strong><strong>}$

ii)) $\huge\frac{1}{3}$

iii)) $\huge\frac{1}{2}$