Question

In figure 1.74, PM=10cm
A(∆PQR)=100sq.cm
A(∆QRS)=110sq.cm
then find NR. ​

Answer 1

Given,

• PM=10cm
• A(∆PQR)=100cm²
• A(∆QRS)=110cm²

To find,

• NR

Proof,

$\pink\dashrightarrow{\Large{\sf{\frac{A(\triangle \: PQS)}{A(\triangle \: QRS)} = \frac{100}{110}}}}$

$\pink\dashrightarrow{\Large{\sf{\frac{\frac{1}{2}\times PM\implies QS}{\frac{1}{2}\times RN \times QS} = \frac{10}{11}}}}$

$\pink\dashrightarrow{\Large{\sf{\frac{\cancel{10}}{RN}={\frac{\cancel{10}}{11}}}}}$

$\green\dashrightarrow{\boxed{\bf{RN = 11cm}}}$