In figure 1.75, A–D–C and B–E–C seg DE || side AB If AD= 5,DC=3,BC=6.4 then find BE.
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Solution:
Given:
In ∆ABC ,
DE \\ AB
AD = 5 , DC = 3 ,
BC = 6.4 ,
Find BE = x = ?
proof :
In ∆ABC ,. DE \\ AB
BE/EC = AD/DC
( Corresponding sides are in
proportional )
[ By Thales theorem ]
x/(6.4-x) = 5/3
=> x × 3 = 5(6.4-x)
=> 3x = 32 - 5x
=> 3x + 5x = 32
=> 8x = 32
=> x = 32/8
=> x = 4
Therefore ,
x = BE = 4
••••
Given:
In ∆ABC ,
DE \\ AB
AD = 5 , DC = 3 ,
BC = 6.4 ,
Find BE = x = ?
proof :
In ∆ABC ,. DE \\ AB
BE/EC = AD/DC
( Corresponding sides are in
proportional )
[ By Thales theorem ]
x/(6.4-x) = 5/3
=> x × 3 = 5(6.4-x)
=> 3x = 32 - 5x
=> 3x + 5x = 32
=> 8x = 32
=> x = 32/8
=> x = 4
Therefore ,
x = BE = 4
••••
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