Question

In figure 1 a parallelogram is drawn in a trapezuim If the area of the paralleogram is 390 cm^2 , find the area of trapezium.

Answer 1

QUESTION➡

In figure 1 a parallelogram is drawn in a trapezuim If the area of the paralleogram is 390 cm^2 , find the area of trapezium.

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ANSWER➡

$Area \: \: of \: \: parallelogram= 390 cm{}^{2}$

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To find the height,

Area of parallelogram= Base× Height

=> 390= 15× height

=> height= 390/15

=> height= 26 cm

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IN THE CASE OF TRIANGLE,

Base = 25- 15 = 10 cm

Height= 26 cm

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$Area \: \: of \: \: triangle = \frac{1}{2} \times base \times height$

$= \frac{1}{2} \times 10 \times 26$

$= 5 \times 26$

= 130 square cm

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Area of trapezium= Area of parallelogram + Area of Triangle

= 390+130

$=520cm {}^{2}$

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Therefore,

Area of trapezium is 520 cm^2

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Answer 2

QUESTION➡

In figure 1 a parallelogram is drawn in a trapezuim If the area of the paralleogram is 390 cm^2 , find the area of trapezium.

_______________________________________________

ANSWER➡

$Area \: \: of \: \: parallelogram= 390 cm{}^{2}$

_____________________________________________

To find the height,

Area of parallelogram= Base× Height

=> 390= 15× height

=> height= 390/15

=> height= 26 cm

_____________________________________________

IN THE CASE OF TRIANGLE,

Base = 25- 15 = 10 cm

Height= 26 cm

_____________________________________________

$Area \: \: of \: \: triangle = \frac{1}{2} \times base \times height$

$= \frac{1}{2} \times 10 \times 26$

$= 5 \times 26$

= 130 square cm

_____________________________________________

Area of trapezium= Area of parallelogram + Area of Triangle

= 390+130

$=520cm {}^{2}$

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Therefore,

Area of trapezium is 520 cm^2

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