Question

In figure 1, AB=AD and BC=DC. prove that (i) ABC=~ADC (ii) AC bisects A​

Answer 1

Step-by-step explanation:

this is the full congruence proving part

Answer 2

Step-by-step answer:

(i)- Given, AB = AD and BC = DC

in ∆ ABC and ∆ ADC

AB=AD (given)

BC=DC (given)

AC=AC (common)

So, ∆ABC=~∆ADC (by SSS congruence)

(ii)- ∆ABC=~∆ADC

So, ∆BAC = ∆DAC (by CPCT)

Hence,AC bisects ∆A