Question

In figure 1 given below. Prove that (i) CF>AF (ii) DC>DF. Please answer it correctly!! I'll Mark YOU AS BRAINLIEST!!!!

Answer 1

Step-by-step explanation:

(i) In triangle ABC

ACB=180-60-65=55

In triangle BEC

BCE=180-90-65=25

SO, ACE=55-25=30

Angle opposite CF=90

Angle opposite AF=30

Hence CF>AF as angle opp CF is greater than the angle opposite AF

(ii) In triangle DFC

DFC= 180-90-DCF        ( DCF=25)

DFC=180-90-25=65

Angle opposite DC=65

Angle opp DF= 25

Hence, DC>DF for the same reason as in the first part

Hope that helped you :-)

Answer 2

Answer:

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