in figure . 1 , show that AB // EF
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ayman1111:
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angle B = angle C
(They form alternate interior angles. So, they AB||CD)
angle E+ Angle ECD
150+30
180°
So EF || CD.
If AB||CD and CD || EF
Then,
EF || AB
(They form alternate interior angles. So, they AB||CD)
angle E+ Angle ECD
150+30
180°
So EF || CD.
If AB||CD and CD || EF
Then,
EF || AB
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