in figure 1 , the sides AB,BC,CA of a triangle ABC touch a circle at P,Q,R respectively. of PA=4cm,BP=3cm,AC=11 cm. them find the length of BC
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In2 triangle ABC, we have
BP= BQ = 3cm
AP= AR = 4cm
( tangents drawn from an external point to the circle are equal).
So, RC = AC-AR
=11-4=7cm
Hence RC= CQ= 7 cm
Then, BC= BQ+QC
7+3=10cm
BP= BQ = 3cm
AP= AR = 4cm
( tangents drawn from an external point to the circle are equal).
So, RC = AC-AR
=11-4=7cm
Hence RC= CQ= 7 cm
Then, BC= BQ+QC
7+3=10cm
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