in figure 10.108 PQ is parallel to ab and PR is parallel to BC if QPR is 102 determine angle abc give reasons
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∠ABC = ∠CBK = 78°
Step-by-step explanation:
Given : PQ || AB and PR || BC , ∠QPR = 102°
Construction : AB is produced to meet PR at K
Since, PQ ‖ AB
∠QPR = ∠BKR = 102° (Corresponding angles)
Since, PR ‖ BC
Therefore,
∠RKB + ∠CBK = 180° (Co. interior angles)
∠CBK = 180° – 102°
∠CBK = 78°
∠ABC = ∠CBK = 78°
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