Question

in figure 10.36 A, B and C are three points on a circle with Centre O such that angle BOC equal to 30 degree and Angle aob equal to 60 degree if D is a point on the circle and other than the earth ABC find angle ADC

Answer 1

Given:

∠AOB = 60°

∠BOC= 30°

Here,∠AOC = ∠AOB + ∠BOC

∠AOC = 60°+30°

∠AOC = 90°

Since Arc ABC makes an angle of 90° at the centre of the circle.

∠ADC= 1/2∠AOC

[SINCE THE ANGLE SUBTENDED BY AN ARC AT THE CENTRE IS DOUBLE THE ANGLE SUBTENDED BY IT AT ANY POINT ON THE REMAINING PART OF THE CIRCLE]


∠ADC= 1/2(90°)

∠ADC= 45°

Hence, ∠ADC= 45°

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Hope this will help you....

Answer 2

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