Question

In figure 10.48 POQ is a line , Ray OR is perpendicular to line PQ . OS is another ray lying between rays OP and OR .Prove that angle ROS = 1/2( angle QOS - angle POS).


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Answer 1

Answer:

∠ROS=90°−∠POS−(i)

∠QOS=∠QOR+∠ROS=90°+∠ROS

⇒90 ∘=∠QOS−∠ROS−(ii)

Substituting (ii) in (i) we get

∠ROS=∠QOS−∠ROS−∠POS

⇒2∠ROS=∠QOS−∠POS

⇒∠ROS= 1/2(∠QOS−∠POS)

Hence proved.

Answer 2

Answer:

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