in figure (10.53) if AC parallel DE, then find the value of x
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angle EDC and angle DCA are alternate angles
EDC=DCA
55°=DCA
DCA=55
Now DCA and BCA are linear pair of angles
DCA+BCA=180°
55+X=180°
X=180-55
=125°
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angle FCB+angle ACB =180°
so angle ACB= 125°
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