Question

In figure 11, AD and CE are respectively perpendicular to sides BC and AB of angle ABC. If angle ECD = 45° , find angle BAD

Answer 1

Answer:

45°

Step-by-step explanation:

Angle BEC is 90°

So, in triangle BEC,

Angle EBC+ angle BEC + angle BCE = 180°

Angle EBC+ 90+45= 180

Angle EBC=180- 135

Angle EBC= 45

Now, angle ADB is 90°

so, in triangle ADB,

Angle ADB+ angle ABD + angle BAD= 180

Angle BAD + 90+45=180

angle BAD= 180-135

angle BAD= 45