Question

In figure 11 , BC and AD intersect at E.
i. prove that triangle CED congruent to triangle BEA

ii. find BA and CD

Answer 1

( i ). In triangle, CED and BEA,

CE = BE = 6cm

Angle CED = Angle BEA [ Vertically Opposite Angles ]

Angle C = Angle B = 90°

So, triangle CED ≅ triangle BEA

( ii ). So, From ( i ) part, the remaining sides will also be equal.

CD = AB

3x + 2 = x + 6

3x - x = 6 - 2

2x = 4

x = 4/2 = 2

BA = x + 6 = 2 + 6 = 8 cm

CD = 3 ( 2) + 2 = 6 +2 = 8cm.

Answer 2

Answer:

the finale ans. of the question is 8 cm