Question

in figure 11, two lines AB and CD intersect at O such that angle BOC=145° find the remaining angles ​

Answer 1

Answer:

Given: BOC =145 degree

DOA=145 degree (opposite angles are equal)

AOC =35 degree (linear pair)

BOD =35 degree (opposite angles of AOC)

Step-by-step explanation:

hope this is helpful

Answer 2

GIVEN : boc = 145

aod = boc.........[opposite angles are equal ]

bod = coa .........[opposite angles are equal ]

aod = 145

let bod & coa be = x

sum of all angles = 360

EQUATION

= aod + boc +bod +coa = 360

= 145 + 145 + x + x = 360

= 290 + 2x = 360

= 2x =360-290

= 2x = 70

= x = 70/2

= x = 35

COA=35

BOD=35

AOD=145

BOC=145

HOPE IT IS HELPFUL