Question

in figure 14.3 3 if angle abc is equal to 50 degree and Angle bdc is equal to 40 degree calculate first angle c d a second angle BAC and third angle BCA​

Answer 1

∠CDA = 50°  , ∠BCA = 90°  & ∠BAC = 40°

Step-by-step explanation:

Assuming AB is Diameter

Then  ∠ BDA = 90°

∠BDA = ∠BDC + ∠CDA

=> 90° = 40°  +  ∠CDA

=>  ∠CDA = 50°

AB is Diameter

Then ∠BCA = 90°

in ΔABC

∠BAC + ∠ABC + ∠BCA = 180°

=> ∠BAC + 50° + 90° = 180°

=> ∠BAC = 40°

Answer 2

Step-by-step explanation:

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