Question

In figure 14 AB || CD . Transversal t cuts AB at E and CD at F. If EG and FH are the bisectors of alternate angles /BEF and /EFC, respectively, prove that EG || HF.​

Answer 1

Answer:

Step-by-step explanation:

Line AB || Line CD

On transversal EF

Angle AGH =Angle GHD.....(1)(alternate angle theorem)

AGH =2 LGH ...(2) (Angle bisector)

GHD=2 MHG....(3)(Angle bisector)

From 1, 2, and 3: LGH = MHG

Therefore line GL || line HM.... (Alternate angle test).

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Answer 2

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